计算指定范围内能整除的个数及总和 

                    计算指定范围内能被3 和 7 整除的个数及总和

1、递归实现：
 1 def count_and_sum(start,end,a=0,b=0):
 2     if start == end:
 3         return a,b
 4 
 5     if start%3 == 0 and start%7 == 0:
 6         a += 1
 7         b += start
 8 
 9     return count_and_sum(start + 1 ,end,a,b)
10 
11 counting,total_sum = count_and_sum(1,998)
12 print("个数是%d, 总和是%d"%(counting,total_sum ))
View Code

只能计算到998，否则RecursionError: maximum recursion depth exceeded in comparison


2、列表生成式实现






 1 def count_and_sum(start=0,end=0):
 2 
 3     num_list = [num for num in range(start,end + 1) if num % 3 == 0 and num % 7 ==0]
 4 
 5     return len(num_list),sum(num_list )
 6 
 7 counting,total_sum = count_and_sum(1,14333345)
 8 
 9 
10 print("个数是%d, 总和是%d"%(counting,total_sum ))



View Code




 






3、生成器实现






 1 def count_and_sum(start=0,end=0):
 2 
 3     gen_num = (num for num in range(start,end + 1) if num % 3 == 0 and num % 7 ==0)
 4 
 5     counting = total_sum = 0
 6 
 7     for num in gen_num:
 8         counting += 1
 9         total_sum += num
10     return counting,total_sum
11 
12 counting,total_sum = count_and_sum(1,14333345)
13 
14 print("个数是%d, 总和是%d"%(counting,total_sum ))



View Code


 




 






            

            
posted @ 
2018-07-28 08:25 
沧海一粒水 
阅读(314) 
评论(0) 
编辑 
收藏 
举报