1.找两个数下标Two Sum

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:

Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].
用字典,存储当前值的下标,判断是否存在target - nums[i]
  1. public class Solution {
  2. public int[] TwoSum(int[] nums, int target) {
  3. if (nums == null || nums.Length < 1) {
  4. return null;
  5. }
  6. Dictionary<int, int> dict = new Dictionary<int, int>();
  7. for (int i = 0; i < nums.Length; i++) {
  8. if (dict.ContainsKey(target - nums[i])) {
  9. int[] arr = { dict[target - nums[i]], i};
  10. return arr;
  11. } else {
  12. dict[nums[i]] = i;
  13. }
  14. }
  15. return null;
  16. }
  17. }





posted @ 2017-02-01 22:58  xiejunzhao  阅读(159)  评论(0编辑  收藏  举报