亲测,下面方法可以实现create table tab1 select * from tab2;
var docs = db.tab1.find({"checked":false}).limit(0,500);
docs.forEach(function(d){db.tab2.insert(d)});
db.tab2.find({"checked":false}).count()
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1、
var result = db.foo.aggregate(...);
db.bar.insert(result.result);
2、测了没实现
var temp1 = db.mtb1.find(name:"joe");
while(temp1.hasNext()) db.tab2.insert(temp1.next());
while(temp1.hasNext()) db.tab2.insert(temp1.next());
相当于sql中:create table tab2 as select * from mtb1 where name='joe';