LeetCode:Validate Binary Search Tree(iupdate)

Given a binary tree, determine if it is a valid binary search tree (BST).

Assume a BST is defined as follows:

  • The left subtree of a node contains only nodes with keys less than the node's key.
  • The right subtree of a node contains only nodes with keys greater than the node's key.
  • Both the left and right subtrees must also be binary search trees.

confused what "{1,#,2,3}" means? > read more on how binary tree is serialized on OJ.

中序遍历验证是否是..

 1 /**
 2  * Definition for a binary tree node.
 3  * struct TreeNode {
 4  *     int val;
 5  *     TreeNode *left;
 6  *     TreeNode *right;
 7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 8  * };
 9  */
10 class Solution {
11     //中序遍历就可以
12 private:
13     TreeNode *prenode;
14 public:
15     bool isValidBST(TreeNode* root) {
16         
17         if(root)
18         {
19         if(!isValidBST(root->left)) return false;
20         if(prenode&&prenode->val>=root->val)
21             return false;
22         prenode=root;
23         
24         if(!isValidBST(root->right)) return false;
25         }
26         return true;
27         
28     }
29     
30    
31 };

 

posted @ 2015-08-18 11:12  尾巴草  阅读(116)  评论(0编辑  收藏  举报