LeetCode:BInary Tree Inorder Traversal(二叉树的中序遍历)

Given a binary tree, return the inorder traversal of its nodes' values.

For example:
Given binary tree {1,#,2,3},

   1
    \
     2
    /
   3

return [1,3,2].

解法一：递归

 1 /**
 2  * Definition for a binary tree node.
 3  * struct TreeNode {
 4  *     int val;
 5  *     TreeNode *left;
 6  *     TreeNode *right;
 7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 8  * };
 9  */
10 class Solution {
11 public:
12     vector<int> inorderTraversal(TreeNode* root) {
13         vector<int> result;
14         inorder(root,result);
15         return result;       
16         
17     }
18     
19     void inorder(TreeNode *node,vector<int> &result)
20     {
21         if(node!=NULL)
22         {
23             inorder(node->left,result);
24             result.push_back(node->val);
25             inorder(node->right,result);
26         }
27         
28     }
29 };

 

posted @ 2015-08-12 11:32  尾巴草  阅读(133)  评论(0)  编辑  收藏  举报