1001. A+B Format (20)

 

时间限制

400 ms

内存限制

32000 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

 

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

C++：

#include <iostream>
#include <string>
#include <sstream>
using namespace std;
int main()
{
int n1,n2,sum;
 
while(cin>>n1)
{
  cin>>n2;
       sum=n1+n2;
  stringstream ss; string s;
  ss<<sum;
  ss>>s;
  int i;
  char ch[20];
  int len=0;int num=0;
 
       for(i=s.length()-1;i>=0;i--)
 {
        ch[len++]=s[i];
             num++;
if(sum>=0&&num==3&&i!=0)   
{
  ch[len++]=',';
  num=0;
}
 if(sum<0&&num==3&&i!=0&&i!=1)   
{
  ch[len++]=',';
  num=0;
}
 }
 
 
        for(i=len-1;i>=0;i--)
cout<<ch[i];
 
cout<<endl;
 
}
   return 0;
}

 

 Python：

 

a,b = raw_input().split( )
a = int(a)
b = int(b)
c = a+b
c = str(c)
n = len(c) - 1 
a = ""
while n >= 0:
    for x in range(0,3):
        a = c[n] + a
        n-=1
        if n < 0:
            break
    if n > 0:
        a = ',' + a
    if n == 0 and c[0] != '-':
        a = ',' + a
print a

 

 

Java

import java.util.*;

public class Main {
    public static void main(String args[])
    {
        Scanner in = new Scanner(System.in);
        int a = in.nextInt();
        int b = in.nextInt();
        in.close();
        int c = a + b;
        String str = Integer.toString(c);
        for(int i = str.length() -3 ; i > 0 ; i = i -3)
        {
            if(!(i==1 && c < 0))
                str = str.substring(0,i) + ',' + str.substring(i,str.length());
        }
        System.out.println(str);
    }
}