html = """
<html><head><title>The Dormouse's story</title></head>
<body>
<p class="title" name="dromouse"><b>The Dormouse's story</b></p>
<p class="story">Once upon a time there were three little sisters; and their names were
<a href="http://example.com/elsie" class="sister" id="link1"><!-- Elsie --></a><a href="http://example.com/lacie" class="sister" id="link2">Lacie</a> and
<a href="http://example.com/tillie" class="sister" id="link3">Tillie</a>
and they lived at the bottom of a well.</p>
<p class="story">...</p></body></html>
"""
soup=BS(html,'html.parser')
for i in soup.find_all('a'):
print('i.text:',i.text)#注释掉的内容就不打印了 str类型
print('i.string:',i.string) #注释掉的内容 都会打印出来，NavigableString对象
print('soup.head.contents:',soup.head.contents,type(soup.head.contents))
print('soup.head.children:',soup.head.children,type(soup.head.children))
print('soup.body.contents:',soup.body.contents)#返回一个子元素的列表
print('soup.body.children:',soup.body.children)#返回一个子元素的迭代器
for i in soup.body.children:
print(i)
print('子孙节点 都显示出来')
for i in soup.body.descendants:
print(i)
print('soup.body.string:',soup.body.string)
print('soup.body.strings:',soup.body.strings)
print('soup.body.stripped_strings:',soup.body.stripped_strings) #过滤掉所有空格显示
print('去掉空格的body子元素：')
for i in soup.body.stripped_strings:
print(i)
print('soup.a.parent:',soup.a.parent)
print('soup.a.next_sibling:',soup.a.next_sibling) #注意文本节点、换行\n都可能成为当前节点的上一个或者下一个同级节点
print('soup.a.previous_sibling:',soup.a.previous_sibling)
print('soup.a.next_element:',soup.a.next_element) #下一个元素 不一定同级
print('soup.a.previous_element:',soup.a.previous_element)
print('打印所有后面的同级节点:\n')
for i in soup.a.next_siblings:
print(i)
print('soup.a.next_element:',list(soup.a.next_elements)[1])
print('***********find_all*****')
print(soup.find_all('a'))
print('引入正则表达式：')
import re
print(soup.find_all(re.compile(r'^title'))) #正则匹配的是 标签的名字
print('列表的方式匹配：')
print(soup.find_all(['a','b']))
print('函数的方式匹配，类似filter')
def func(tag):
if tag.has_attr('class') and re.search(r'^a',tag.name):
return tag
print(soup.find_all(func))
html = """
<html><head><title>The Dormouse's story</title></head>
<body>
<p class="title" name="dromouse"><b>The Dormouse's story</b></p>
<p class="story">Once upon a time there were three little sisters; and their names were
<a href="http://example.com/elsie" class="sister" id="link1"><!-- Elsie --></a><a href="http://example.com/lacie" class="sister" id="link2">Lacie</a> and
<a href="http://example.com/tillie" class="sister" id="link3">Tillie</a>
and they lived at the bottom of a well.</p>
<p class="story">...</p></body></html>
"""
soup=BS(html,'html.parser')
print('按属性值查找:')
print(soup.find_all(id='link1'))
print(soup.find_all('a',id='link1'))
print(soup.find_all(id='link2',href=re.compile(r'laci'))) #返回的都是列表
print(soup.find_all(class_='story')) #注意后面加的下划线
print(soup.find_all(attrs={'class':'sister'}))
print('按元素内容查找text参数：')
print(soup.find_all(text='Tillie'))
print(soup.find_all(text=['Tillie','Lacie'])) #返回的都是元素内容
print(soup.find_all(text=re.compile(r'ormous')))
print('通过内容元素 找到上级元素')
print(soup.find_all(text=re.compile(r'ormous'))[1].parent.parent)
#限制查找数量
print('limit:')
print(soup.find_all('a',limit=2))
print('只在子节点查找：')
print(soup.body.find_all('a',limit=2,recursive=False)) #只查找子节点 recursive循环的、递归的
print(soup.body.find_all(class_='story',recursive=False))
