02 2022 档案
摘要：//评测题目: 无一串无序字符串"asdgartioafhajdskgaulekjnjxjafklefjjqwe",统计每个字母出现的个数 class Test(object): dict1 = {} #定义一个字典用来统计 def count(self,value): for i in value
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摘要：a=[1,1,1,2,2,2,2,6,5,5,5,5] num=[] for i in a: s = a.count(i) num.append(s) num1 = sorted(num,reverse=True) num2=list(set(num1)) num2.sort(key=num1.in
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