java mongodb group后count,再排序
方式1:
Criteria criteria = new Criteria(); criteria.andOperator( Criteria.where("msgTimestamp").gte(beginTime), Criteria.where("msgTimestamp").lte(endTime) ); criteria.and("convType").is(ConvTypeEnum.PERSON.toString()); if (StringUtils.isNotEmpty(fromAccount)) { criteria.and("fromAccount").is(Constants.TJK_PREFIX + fromAccount); } Sort sort0 = new Sort(Sort.Direction.DESC,"_id"); Aggregation aggregation = Aggregation.newAggregation( Aggregation.match(criteria), Aggregation.group("relationId").count().as("ccc"), Aggregation.sort(sort0), Aggregation.limit(10000)); List<DBObject> pvs =this.mongoTemplate().aggregate(aggregation, Constants.SINGLE_MSG_COLLECTION, DBObject.class).getMappedResults();
由于 db.teamTalkSingleMsg.aggregate([{$group : {_id : "$relationId", ccc : {$sum : 1}}}])这一行的“_id”不能写成其他的,所以排序也只能用_id来接
方式2:
//group DBObject groupFields = new BasicDBObject( "_id", "$relationId"); groupFields.put("count", new BasicDBObject( "$sum", 1)); DBObject group = new BasicDBObject("$group", groupFields); //where条件 DBObject condition1 = new BasicDBObject(); condition1.put("convType", ConvTypeEnum.PERSON.toString()); condition1.put("msgTimestamp", new BasicDBObject("$gte", beginTime).append("$lte", endTime)); DBObject match = new BasicDBObject("$match", condition1); //$match相当于where //排序 DBObject sortFields = new BasicDBObject("_id", 1); // 注意此处排序是按照字段day升序,但是不能写day 需用_id代替,因为day是group用的字段 DBObject sort = new BasicDBObject("$sort", sortFields); List<DBObject> optionList = new ArrayList<>(); optionList.add(match); optionList.add(group); optionList.add(sort); //optionList中的顺序很重要,不是随便往list里面加的,否则是不正确的,添加的顺序也是参照上面网址里面的内容 AggregationOutput output = this.mongoTemplate().getCollection(Constants.SINGLE_MSG_COLLECTION).aggregate(optionList);