多测师讲解python_斐波那契数列：_高级讲师肖sir

 

 

 

 

 

def f(n):
    a,b=1,1
    if n==1 or n ==2:
        return 1
    else:
        i=3
        while i<=n:
            a,b=b,a+b
            i+=1
        return b

print(f(int(input(" 斐波那契数列："))))

 

 

 

 

hu= int(input("斐波那契数列："))
new = []
def  a(n):
    if n>=3:
        v=a(n-1)+a(n-2)
    else:
        v=1
    return  v

print("开始")

for i in range(0,shu):
    new.append(new(i+1))
print(new)