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1)求1~100的和方法:
方法一:print(sum(range(1,101)))
方法二:
sum1 = 0
i = 1
while True:
    sum1 = sum1 + i
    if i == 100:
        break
    i += 1
print(sum1)
方法三:


(2)
求1~100的偶数和方法:
方法一:
a = 1
sum = 0
while a <= 100:
if a % 2 == 0:
sum += a
a += 1
print(sum)
方法二:
sum1 = 0
for i in range(1,101):
  if i % 2 == 0:
      sum1 = sum1 +i
   i += 1
print("1-100之间偶数的和是:%d" %sum1)
方法三:
#100以内偶数和 
c=0
s=[i for i in range(1,101)]
for i in s[1::2]:
    c+=i
print  c
 
质数和
i=2
for i in range(2,100):
    j=2
    for j in range(2,i):
        if i %j ==0:
            break
    else:
            sums3+=i
print(sums3)
 

  

#偶数和奇数的和
sum1 = 0
sum2 = 0
while i <= 100:
    if i % 2 == 0:
        sum1 += i
    else:
        sum2 += i
    i +=1
print("1-100之间偶数和为:%d" % sum1)
print("1-100之间奇数和为:%d" % sum2)

  

#偶数-奇数
j= []   #统计奇数
o= []   #统计偶数
i = 1
while i <=100:
    if i % 2 == 0:#用来存放偶数
       o.append(i)
    else:
        j.append(i)
    i+=1
print   j  #把所有的奇数放进odd列表中  结果:1,3,5,7,9
print   o #把所有的偶数放进even列表中      结果:2,4,,6,8,10
print sum(o) - sum(j)

  

 


 

posted on 2020-05-18 13:04  多测师_肖sir  阅读(376)  评论(0编辑  收藏  举报