我的C语言学习笔记<三>

通过输入两个加数给学生出一道加法运算题，如果输入答案正确，则显示“Right!”，否则提示重做，显示“Not correct! Try again!”，最多给三次机会，如果三次仍未做对，则显示“Not correct! You have tried three times! Test over!”，程序结束。

#include <stdio.h>
#include <conio.h>

main()
{
int a,b,sum,k,i=1;
scanf("%d,%d",&a,&b);
printf("%d+%d=",a,b);
scanf("%d",&sum);

while(i<3&&sum!=a+b)
{
printf("input again");
scanf("%d",&sum);
if(sum==a+b)
{printf("right");break;}
else
{
i++;
}
}

if(i>=3) {printf("Not correct! You have tried three times! Test over!"); }
getch();

}

解法二

 

#include <stdio.h>
main()
{
 int a,b,sum,i=0,k;
    printf("shu ru liang ge shu:\n");
   scanf("%d%d",&a,&b);
    printf("%d+%d=\n",a,b);
    sum=a+b;
 do
 {  i++;
    scanf("%d",&k);
    if(k==sum) {printf("right\n");break;}
    if(i>2)
    {printf("Not correct! You have tried three times! Test over!");break;}
    if(k!=sum) printf("Not correct! Try again!\n");

 

}
while(i<=2);
  getch();

 }

解法三

 

#include <stdio.h>
#include <conio.h>

main()
{
int a,b,sum,k,i=0;
scanf("%d,%d",&a,&b);
printf("%d+%d=",a,b);
scanf("%d",&sum);
for(i=0;i<3;i++)
{
if(sum==a+b)
{printf("right");break;}
else
{
printf("input again");
scanf("%d",&sum);

}
}
if(i>=3) {printf("Not correct! You have tried three times! Test over!"); }
getch();

}