将字符串数组转换成整型
int abcd(char arr[])
{
int sum = 0;
char *cha = &arr[0];
int a = 0;
while (*cha != '\0')
{
cha++;
a++;
}
for (int i = 0; i < a; i++)
{
cha--;
}
char ch = *cha;
for (int i = 0; i < a; i++)
{
sum *= 10;
int a = 0;
a = ch - '0';
sum += a;
cha++;
ch = *cha;
}
return sum;
}