摘要: computed: { hasNum() { return this.orderList.reduce((res, cur) => { res += (cur.amount||0)/100 return this.formatNum(res,2) }, 0) } }, formatNum(f, di 阅读全文
posted @ 2021-04-08 14:47 小灬壊 阅读(135) 评论(0) 推荐(0) 编辑