Java练习作业
String str = "Nothing is impossible to a willing heart";
String str2 = "No cross, no crown.";
1, 打印整个字符串去掉所有空格之后的长度
public class Test4{ public static void main(String[] args) { String str = "Nothing is impossible to a willing heart"; String str2 = "No cross, no crown."; System.out.println(str.replace(" ","").length());//用replace替换空格。然后在打印长度。 System.out.println(str2.replace(" ","").length()); } }
输出:
2, 写代码找出字母"o","s"所在字符串str中第一次出现的索引位置, 找出字符串中最后一个"t"的索引位置, 并输出在控制台上
public class Test4{ public static void main(String[] args) { String str = "Nothing is impossible to a willing heart"; String str2 = "No cross, no crown."; System.out.println(str.indexOf("o")); System.out.println(str.indexOf("s")); System.out.println(str.lastIndexOf("t")); }
输出:
3, 写代码实现将str字符串用"空格"分割成数组, 并输出索引值为4的值
public class Test4{ public static void main(String[] args) { String str = "Nothing is impossible to a willing heart"; String str2 = "No cross, no crown."; System.out.println(str.split(" ")[4]);//转换完后就是一个数组,直接在数组去索引值就可以 } }
输出:
4, 写代码实现将str字符串中所有的"i"替换成"I"
public class Test4{ public static void main(String[] args) { String str = "Nothing is impossible to a willing heart"; String str2 = "No cross, no crown."; System.out.println(str.replace("i","I")); } }
输出:
5, 编写代码从str字符串中取每个单词的首字母打印在控制台上
public class Test4{ public static void main(String[] args) { String str = "Nothing is impossible to a willing heart"; String str2 = "No cross, no crown."; String[] strArray = str.split(" ");//把str分解为用空格隔开的几个数字(每个单词是一个数组) for (int i = 0; i < strArray.length; i++) { System.out.println(strArray[i].charAt(0));//获取新数组索引为0的值。 } } }
输出:
6, 在不使用第三个变量的情况下互换str和str2的值
public class Test4{ public static void main(String[] args) { String str = "Nothing is impossible to a willing heart"; String str2 = "No cross, no crown."; System.out.println("str=" +str . replace(str,str2)) ; System.out.println("str2=" +str2 . replace(str2,str)) ; } }
输出:
第二种方法
public class Test4{ public static void main(String[] args) { String str = "Nothing is impossible to a willing heart"; String str2 = "No cross, no crown."; str += str2;//str和str2拼接 str=str+str2 str2 = str.substring(0, str.length() - str2.length());//截取str从0到str长度减str2的长度相当于"Nothing is impossible to a willing heart No cross, no crown."-" No cross, no crown." str = str.substring(str2.length());//截取从str2长度(包括)开始相当于从" No cross, no crown."开始到最后 System.out.println("str=" + str); System.out.println("str2=" + str2); } }