/*
* linux/kernel/mktime.c
*
* Copyright (C) 1991, 1992 Linus Torvalds
*/
#include <linux/mktime.h>
/*
* This isn't the library routine, it is only used in the kernel.
* as such, we don't care about years<1970 etc, but assume everything
* is ok. Similarly, TZ etc is happily ignored. We just do everything
* as easily as possible. Let's find something public for the library
* routines (although I think minix times is public).
*/
/*
* PS. I hate whoever though up the year 1970 - couldn't they have gotten
* a leap-year instead? I also hate Gregorius, pope or no. I'm grumpy.
*/
#define MINUTE 60 //1分钟60秒
#define HOUR (60*MINUTE) //一小时 60 * MINUTE秒
#define DAY (24*HOUR) //一天有多少秒
#define YEAR (365*DAY) //一年有多少秒
/* interestingly, we assume leap-years */
//假设为闰年,计算每个月过去秒数
static int month[12] = {
0, //进入新的一年过去的秒数
DAY*(31), //一月过去之后占用的秒数
DAY*(31+29), //二月过去之后占用的秒数
DAY*(31+29+31), //三月过去之后占用的秒数
DAY*(31+29+31+30), //四月过去之后占用的秒数
DAY*(31+29+31+30+31), //五月过去之后占用的秒数
DAY*(31+29+31+30+31+30), //六月过去之后占用的秒数
DAY*(31+29+31+30+31+30+31), //七月过去之后占用的秒数
DAY*(31+29+31+30+31+30+31+31), //八月过去之后占用的秒数
DAY*(31+29+31+30+31+30+31+31+30), //九月过去之后占用的秒数
DAY*(31+29+31+30+31+30+31+31+30+31), //十月过去之后占用的秒数
DAY*(31+29+31+30+31+30+31+31+30+31+30) //十一月过去之后占用的秒数(12月过去要计算整年)
};
//初始化内核时间
long kernel_mktime(struct mktime * time)
{
long res;
int year;
year = time->year - 70; //从1970年一月0点0分0秒
/* magic offsets (y+1) needed to get leapyears right.*/
res = YEAR*year + DAY*((year+1)/4); //从计时时间开始到今年共有多少秒
res += month[time->mon]; //加上已经过去的月份的秒数(假设为闰年)
/* and (y+2) here. If it wasn't a leap-year, we have to adjust */
if (time->mon>1 && ((year+2)%4)) //判断是否为闰年,并且是否过了二月,进行时间调整
res -= DAY;
res += DAY*(time->day-1); //加上这个月过去的天数所占有的秒数
res += HOUR*time->hour; //加上过去的小时数占有的秒数
res += MINUTE*time->min; //加上过去的分钟数占有的秒数
res += time->sec; //加上过去的秒数
return res; //结果为计时开始到现在为止过去的秒数
}