旋转数组的最小数字

#include <iostream>
#include <stdio.h>

using namespace std;
int inorder(int a[],int index1, int index2)
{
    int mini=index1;
    for(int i = index1 + 1;i <= index2; i++)
        if(a[mini]>a[i])
            a[mini]=a[i];
    return a[mini];
}
int Min(int a[],int len)
{
    int index1 = 0;
    int index2 = len-1;
    int mid = index1;
    while(a[index1] >= a[index2])
    {
        if(index2 - index1 ==1)
            return a[index2];
        mid = (index1 + index2)/2;

        if( a[mid] == a[index1] && a[index1] == a[index2])
            return inorder(a,index1,index2);

        if(a[mid] > a[index1])
            index1 = mid;
        else
            if(a[mid]<a[index2])
                index2 = mid;
    }
    return a[mid];
}
int main()
{
    int a[5]={3,4,5,0,2};
    cout << Min(a,5) << endl;
    return 0;
}