LeetCode Easy: 48. Rotate Image
一、题目
You are given an n x n 2D matrix representing an image.
Rotate the image by 90 degrees (clockwise).
Note:
You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.
Example 1:
Given input matrix = [ [1,2,3], [4,5,6], [7,8,9] ], rotate the input matrix in-place such that it becomes: [ [7,4,1], [8,5,2], [9,6,3] ]
Example 2:
Given input matrix = [ [ 5, 1, 9,11], [ 2, 4, 8,10], [13, 3, 6, 7], [15,14,12,16] ], rotate the input matrix in-place such that it becomes: [ [15,13, 2, 5], [14, 3, 4, 1], [12, 6, 8, 9], [16, 7,10,11] ]
题意:给定一个矩阵,顺时针旋转90度。
二、思路
三、代码
#coding:utf-8 import numpy as np class Solution: def rotate(self, matrix): """ :type matrix: List[List[int]] :rtype: void Do not return anything, modify matrix in-place instead. """ print("old:",'\n', matrix) n = np.shape(matrix)[0] # 沿着副对角线反转 for i in range(n): for j in range(n-i): temp = matrix[i][j] matrix[i][j] = matrix[n-1-j][n-1-i] matrix[n-1-j][n-1-i] = temp #沿着水平中线反转 for i in range(n//2): for j in range(n): temp = matrix[i][j] matrix[i][j] = matrix[n-1-i][j] matrix[n-1-i][j] = temp print('new:','\n', matrix) if __name__ == '__main__': a = [[1,2,3], [4,5,6], [7,8,9] ] ss = Solution() ss.rotate(a)
既然无论如何时间都会过去,为什么不选择做些有意义的事情呢