Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight).
For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011
, so the function should return 3.
求一个无符号int的二进制中的1的个数。
public class Solution { // you need to treat n as an unsigned value public int hammingWeight(int n) { int result = 0; for (int i = 0; i < 32; i++){ if ((n & 1) == 1){ result++; } n >>= 1; } return result; } }