Given an array of integers, every element appears twice except for one. Find that single one.

Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

 

求出数组中只出现了一次的数(其他的数都出现了2次)

 

 

异或求解。

 

public class Solution {
    public int singleNumber(int[] nums) {
        int len = nums.length;
        int result = nums[0];
        for( int i = 1;i<len;i++){

            result = result^nums[i];

        }
        return result;
    }
}