leetcode 128. Longest Consecutive Sequence ----- java

Given an unsorted array of integers, find the length of the longest consecutive elements sequence.

For example,
Given [100, 4, 200, 1, 3, 2],
The longest consecutive elements sequence is [1, 2, 3, 4]. Return its length: 4.

Your algorithm should run in O(n) complexity.

 

就是判断数组中最长的连续数字的长度。

1、直接用排序。。当然不行了，时间复杂度超过了O(n)，虽然AC了。

public class Solution {
    public int longestConsecutive(int[] nums) { 
        int result = 1;
        if( nums.length == 0)
            return result;
        Arrays.sort(nums);
        for( int i = 1;i<nums.length;i++){
            int a = 1;
            while( i<nums.length && (nums[i] == nums[i-1]+1 || nums[i] == nums[i-1]) ){
                if( nums[i] == nums[i-1]+1 )
                    a++;
                i++;
            }
            result = Math.max(a,result);
            
        }
        return result;
        
    }
}

2、用set集合。遍历两次，得出结果，由于add，remove，contains都是O(1)的复杂度，所以时间复杂度符合题意。

public class Solution {
    public int longestConsecutive(int[] nums) { 
        if( nums.length == 0)
            return 0;
        Set set = new HashSet<Integer>();

        for( int num : nums)
            set.add(num);
        int result = 1;

        for( int e : nums){
            int left = e-1;
            int right = e+1;
            int count = 1;
            while( set.contains(left )){
                set.remove(left);
                count++;
                left--;
            }
            while( set.contains(right) ){
                set.remove(right);
                count++;
                right++;
            }
            result = Math.max(result,count);


        }
    return result;
        
    }
}