hdu4055 dp[i][j]表示第i位以j结尾的方案数(long long 超时)

 1 #include<stdio.h>
 2 #include<string.h>
 3 #define MOD  1000000007
 4 int dp[1005][1005],sum[1005][1005];
 5 char s[1005];
 6 int main()
 7 {
 8     int len,i,j;
 9     while (~scanf("%s",s+2))
10     {
11         len=strlen(s+2);
12         memset(dp,0,sizeof(dp));
13         memset(sum,0,sizeof(sum));
14         dp[1][1]=1; sum[1][1]=1;
15         for (i=2;i<=len+1;i++)
16             for (j=1;j<=i;j++)
17         {
18             if (s[i]=='I'||s[i]=='?') dp[i][j]=sum[i-1][j-1]%MOD;
19             if (s[i]=='D'||s[i]=='?') dp[i][j]=((sum[i-1][i-1]+MOD-sum[i-1][j-1])%MOD+dp[i][j])%MOD;
20             sum[i][j]=(sum[i][j-1]+dp[i][j])%MOD;
21         }
22         printf("%d\n",sum[len+1][len+1]);
23     }
24 }

http://acm.hdu.edu.cn/showproblem.php?pid=4055

posted on 2014-10-27 21:58  xiao_xin  阅读(146)  评论(0编辑  收藏  举报

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