摘要：
摘自 http://blog.csdn.net/coolbacon/article/details/4042054clear;clc;m1 = [[0 2];[3 1]];u1=ones(2, 2);m2=[[4*m1 4*m1+2*u1];[4*m1+3*u1 4*m1+u1]]u2=ones(4, 4);m3=[[4*m2 4*m2+2*u2];[4*m2+3*u2 4*m2+u2]]I = imread('E:\\beichuan1.jpg');gI = .2989*I(:,:,1)... +.5870*I(:,:,2)... +.1140*I(:,:,3);[h w] 阅读全文
