How to use Javascript JSON.stringify similar method in Python All In One

How to use Javascript JSON.stringify similar method in Python All In One

如何在 Python 中使用类似 JavaScript JSON.stringify 的方法

应用场景

比较两个数组(列表)对象是否相等 / compares two array (list) objects for equality

// js
arr1 = [1,2,3]
arr2 = [1,2,3]

JSON.stringify(arr1) === JSON.stringify(arr2)

# python
import json

list1 = [1,2,3]
list2 = [1,2,3]

json.dumps(list1) == json.dumps(list2)

demos

比较两个列表是否相等

import json

list1 = [1,2,3]
list2 = [1,2,3]

result = json.dumps(list1) == json.dumps(list2)
print("result =", result)

""" 

$ py3 ./json.stringify_json.dumps.py
result = True

"""

比较两个链表是否相等

# Definition for singly-linked list.

from typing import Optional

class ListNode:
  def __init__(self, val=0, next=None):
    self.val = val
    self.next = next

class Solution:
  def middleNode(self, head: Optional[ListNode]) -> Optional[ListNode]:
    # DFS / BFS
    def getLength(node):
      temp = node
      length = 1;
      while temp.next != None:
        length += 1
        temp = temp.next
      return length
    def dfs(node, length):
      temp = node
      # 向下取整除法
      l = length // 2
      while l > 0:
        l -= 1
        temp = temp.next
      return temp
    return dfs(head, getLength(head))


def SingleLinkedListGenerator(num: int, start: int = 1) -> Optional[ListNode]:
  head = ListNode()
  temp = head
  for i in range(num):
    if(start == 1):
      temp.next = ListNode(i + start)
      # print("temp.next.val =", temp.next.val)
      temp = temp.next
    else:
      if(i < start):
        temp.next = ListNode(i + start)
        # print("temp.next.val =", temp.next.val)
        temp = temp.next
  return head.next

# 比较两个链表是否相等
def compareListEqual(one, two):
  while one and two and one.val == two.val:
    one = one.next
    two = two.next
  # 同时为 None ✅
  if not one and not two:
    return True
  return False

input = SingleLinkedListGenerator(7)
# print("\n")
result = SingleLinkedListGenerator(7, 4)
# i = [1,2,3,4,5,6,7]
# r = [4,5,6,7]

solution = Solution()
case = solution.middleNode(input)

test = compareListEqual(case, result)
if test:
  print("✅ test =", test)
else:
  print("❌ test =", test)

# how to compare two linked lists are equal in Python ??? JSON.stringify(list)
# https://www.cnblogs.com/xgqfrms/p/17626511.html

# # test cases
# t1 = 14
# t2 = 8
# t3 = 123
# tests = [t1, t2, t3]

# r1 = 6
# r2= 4
# r3 = 12
# results = [r1, r2, r3]

# def test():
#   solution = Solution()
#   for index, test in enumerate(tests):
#     value = solution.numberOfSteps(test)
#     result = results[index]
#     if(str(value) == str(result)):
#       print("✅ passed", index)
#     else:
#       print("❌ failed", value, result)

# test()


""" 

$ py3 ./876_middle-of-the-linked-list.py


https://leetcode.com/problems/middle-of-the-linked-list/

https://www.cnblogs.com/xgqfrms/p/17624242.html

"""

https://www.cnblogs.com/xgqfrms/p/17624242.html

JSON encoder and decoder

import json

json.dumps([1, 2, 3, {'4': 5, '6': 7}], separators=(',', ':'))
// '[1,2,3,{"4":5,"6":7}]'

https://docs.python.org/3/library/json.html

https://docs.python.org/2/library/json.html

refs

https://stackoverflow.com/questions/46227854/json-stringify-javascript-and-json-dumps-python-not-equivalent-on-a-list

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