VSCode for LeetCode TestCase Template All In One
VSCode for LeetCode TestCase Template All In One
VSCode for LeetCode 测试用例模版
"use strict";
/**
*
* @author xgqfrms
* @license MIT
* @copyright xgqfrms
* @created 2022-07-04
* @modified
*
* @description 459. Repeated Substring Pattern
* @description 459. 重复的子字符串
* @difficulty Easy
* @time_complexity O(n)
* @space_complexity O(n)
* @augments
* @example
* @link https://leetcode.com/problems/repeated-substring-pattern/
* @link https://leetcode-cn.com/problems/repeated-substring-pattern/
* @solutions
*
* @best_solutions
*
*/
const log = console.log;
/**
* @param {string} s
* @return {boolean}
*/
var repeatedSubstringPattern = function(s) {
const len = s.length;
if(len < 2) {
return false;
}
// write your code here
let temp = '';
for(let i = 0; i < (len / 2); i++) {
temp += s[i];
const reg = new RegExp(temp, 'g');
const left = s.replace(reg, '');
if(!left.length) {
return true;
}
}
return false;
}
// 如果是的话,字符串一定是其子串的整数的倍数, 贪心算法
// 测试用例 test cases
const testCases = [
{
input: 'abab',
result: true,
desc: 'value equal to true',
},
{
input: 'aba',
result: false,
desc: 'value equal to false',
},
{
input: 'abcabcabcabc',
result: true,
desc: 'value equal to true',
},
{
input: 'a',
result: false,
desc: 'value equal to false',
},
{
input: 'abaababaab',
// "abaab"
result: true,
desc: 'value equal to true',
},
{
input: 'babbabbabbabbab',
// "bab"
result: true,
desc: 'value equal to true',
},
];
for (const [i, testCase] of testCases.entries()) {
const result = repeatedSubstringPattern(testCase.input);
log(`test case i result: `, result === testCase.result ? `✅ passed` : `❌ failed`, result);
// log(`test case i =`, testCase);
}
KMP 算法
https://en.wikipedia.org/wiki/Knuth–Morris–Pratt_algorithm
https://zh.wikipedia.org/wiki/KMP算法
https://www.geeksforgeeks.org/kmp-algorithm-for-pattern-searching/
refs
https://github.com/xgqfrms/vscode/issues/53
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