Typescript & LinkedList All In One
Typescript & LinkedList All In One
"use strict";
/**
*
* @author xgqfrms
* @license MIT
* @copyright xgqfrms
* @created 2022-02-09
* @modified
*
* @description Typescript & LinkedList All In One
* @augments
* @example
* @link
*
*/
const log = console.log;
function ListNode(this: any, val: any, next: any = undefined) {
// constructor() {}
this.val = (val === undefined ? 0 : val)
this.next = (next === undefined ? null : next)
}
// function ListNode(val: any, next: any = undefined) {
// // constructor() {}
// this.val = (val === undefined ? 0 : val)
// this.next = (next === undefined ? null : next)
// }
// 'this' implicitly has type 'any' because it does not have a type annotation.ts(2683)
let arr = [2, 4, 3];
let root = new (ListNode as any)(arr.pop());
// let root = new ListNode(arr.pop());
let head = root;
log('head ', head);
while (arr.length) {
if (!head.next) {
const value = arr.pop();
head.next = new (ListNode as any)(value);
// head.next = new ListNode(value);
log('head.next ', head.next);
head = head.next;
}
}
// 'new' expression, whose target lacks a construct signature, implicitly has an 'any' type.ts(7009)
log('root ', root);
export {};
refs
https://leetcode.com/problems/add-two-numbers/
https://www.cnblogs.com/xgqfrms/p/15873147.html#5011112
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本文首发于博客园,作者:xgqfrms,原文链接:https://www.cnblogs.com/xgqfrms/p/15873454.html
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