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使用 js 实现十大排序算法: 快速排序 All In One

使用 js 实现十大排序算法: 快速排序

QuickSort

快速排序

/**
 *
 * @author xgqfrms
 * @license MIT
 * @copyright xgqfrms
 * @created 2020-10-01
 * @modified
 *
 * @description 快速排序 quicksort
 * @difficulty Medium
 * @complexity O(n*log(n))
 * @augments
 * @example
 * @link https://www.cnblogs.com/xgqfrms/p/13857663.html
 * @link https://leetcode.com/problems/kth-largest-element-in-an-array/
 * @link https://leetcode.cn/problems/kth-largest-element-in-an-array/
 * @solutions
 *
 */

const log = console.log;

function quickSort(arr) {
  // 终止条件 ✅
  if (arr.length <= 1) {
    return arr;
  }
  // 中间 index
  let pivotIndex = Math.floor(arr.length / 2);
  // 截取中间值,✅ splice 改变原数组长度,  ❌ slice 不改变原数组长度
  const pivot = arr.splice(pivotIndex, 1)[0];
  const left = [];
  const right = [];
  for (let i = 0; i < arr.length; i++) {
    if (arr[i] < pivot) {
      left.push(arr[i]);
    } else {
      right.push(arr[i]);
    }
  }
  // 递归
  return quickSort(left).concat([pivot], quickSort(right));
};


const arr = [12, 7, 5, 23, 18, 37, 1, 9, 17];

const test = quickSort(arr);

log(`arr =\n`, arr)
log(`test =\n`, test)

TypeScript

"use strict";

/**
 *
 * @author xgqfrms
 * @license MIT
 * @copyright xgqfrms
 * @created 2023-01-01
 * @modified
 *
 * @description
 * @description
 * @difficulty Easy Medium Hard
 * @ime_complexity O(n)
 * @space_complexity O(n)
 * @augments
 * @example
 * @link https://www.cnblogs.com/xgqfrms/p/13947110.html
 * @solutions
 *
 * @best_solutions
 *
 */

// export {};

const log = console.log;

function quickSort(arr: number[]): number[] {
  // 终止条件 ✅
  if (arr.length <= 1) {
    return arr;
  }
  // 中间值
  let index = Math.floor(arr.length / 2);
  let mid = arr[index];
  // 新数组
  arr = [...arr.slice(0, index), ...arr.slice(index+1)];
  const left: number[] = [];
  const right: Array<number> = [];
  for (let i = 0; i < arr.length; i++) {
    if (arr[i] < mid) {
      left.push(arr[i]);
    } else {
      right.push(arr[i]);
    }
  }
  // 递归
  return [...quickSort(left), mid, ...quickSort(right)];
};


// 测试用例 test cases
const testCases = [
  {
    input: [12, 7, 5, 23, 18, 37, 1, 9, 17],
    result: [1, 5, 7, 9, 12, 17, 18, 23, 37],
    desc: 'value equal to [1, 5, 7, 9, 12, 17, 18, 23, 37]',
  },
  {
    input: [2, 1],
    result: [1, 2],
    desc: 'value equal to [1, 2]',
  },
  {
    input: [1],
    result: [1],
    desc: 'value equal to [1]',
  },
  {
    input: [],
    result: [],
    desc: 'value equal to []',
  },
];

for (const [i, testCase] of testCases.entries()) {
  const result = quickSort(testCase.input);
  log(`test case ${i} result: `, JSON.stringify(result) === JSON.stringify(testCase.result) ? `✅ passed` : `❌ failed`, result);
}

// $ npx ts-node ./quick-sort.ts


image

Array.slice

image

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/slice

demos

leetcode: 215. 数组中的第K个最大元素

"use strict";

/**
 *
 * @author xgqfrms
 * @license MIT
 * @copyright xgqfrms
 * @created 2022-08-0
 * @modified
 *
 * @description 215. Kth Largest Element in an Array
 * @description 215. 数组中的第K个最大元素
 * @difficulty Medium
 * @ime_complexity O(n)
 * @space_complexity O(n)
 * @augments
 * @example
 * @link https://leetcode.com/problems/kth-largest-element-in-an-array/
 * @link https://leetcode.cn/problems/kth-largest-element-in-an-array/
 * @solutions
 *
 * @best_solutions
 *
 */

export {};

const log = console.log;

// function findKthLargest(nums: number[], k: number): number {
//   return nums.sort((a,b) => b - a)[k - 1];
// };

function findKthLargest(nums: number[], k: number): number {
  // 快排
  function quickSort(arr: number[]) {
    // 终止条件 ✅
    if(arr.length <= 1) {
      return arr;
    }
    let index = Math.floor(arr.length / 2);
    let mid = arr.splice(index, 1)[0];
    let left: number[] = [];
    let right: number[] = [];
    for(const i of arr) {
      // 降序
      if(i >= mid) {
        left.push(i);
      } else {
        right.push(i);
      }
    }
    return [...quickSort(left), mid, ...quickSort(right)];
  }
  const arr = quickSort(nums);
  return arr[k - 1];
};

type TestCase = {
  inputs: [number[], number];
  [key: string]: any;
}

// 测试用例 test cases
const testCases: TestCase[] = [
  {
    inputs: [[3,2,1,5,6,4], 2],
    result: 5,
    desc: 'value equal to 5',
  },
  {
    inputs: [[3,2,3,1,2,4,5,5,6], 4],
    result: 4,
    desc: 'value equal to 4',
  },
];

for (const [i, testCase] of testCases.entries()) {
  // const [first, second] = testCase.inputs as [number[], number];
  const [first, second] = testCase.inputs;
  const result = findKthLargest(first, second);
  log(`test case ${i} result: `, JSON.stringify(result) === JSON.stringify(testCase.result) ? `✅ passed` : `❌ failed`, result);
}


// $ npx ts-node ./215\ kth-largest-element-in-an-array.ts

/*

test case 0 result:  ✅ passed 5
test case 1 result:  ✅ passed 4

*/


refs

js 十大排序算法 All In One

https://www.cnblogs.com/xgqfrms/p/13947122.html

https://www.cnblogs.com/xgqfrms/p/13857663.html

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posted @ 2020-11-09 21:13  xgqfrms  阅读(143)  评论(3编辑  收藏  举报