函数的重载

    public class MainTest
    {
        public static void Main()
        {
            BaseMyClass baseMy=new BaseMyClass();
            IntMyClass IntMy=new IntMyClass();
            BaseMyClass IntMy2=new IntMyClass();
            
            baseMy.ShowMessage1();
            baseMy.ShowMessage2();

            IntMy.ShowMessage1();
            IntMy.ShowMessage2();

            IntMy2.ShowMessage1();
            IntMy2.ShowMessage2();

            Console.ReadLine();

        }
    }
    public class BaseMyClass
    {
        public void ShowMessage1()
        {
            Console.WriteLine("Base1");
        }
        public virtual void ShowMessage2()
        {
            Console.WriteLine("Base2");
        }

    }
    
    public class IntMyClass:BaseMyClass
    {
        public new void ShowMessage1()
        {
            Console.WriteLine("IntMy1");
        }
        public override void ShowMessage2()
        {
            Console.WriteLine("IntMy2");
        }

    }

以上代码执行的结果为:
Base1
Base2
IntMy1
IntMy2
Base1
IntMy2

如果把IntMyClass中函数ShowMessage1的new去掉后执行的结果
Base1
Base2
IntMy1
IntMy2
Base1
IntMy2
没有区别

如果将IntMyClass中函数ShowMessage2的override去掉执行的结果为
Base1
Base2
IntMy1
IntMy2
Base1
Base2
:)