2的10次方

#include <iostream>

int main()
{
        int value = 2, counts = 10, res = 1;
        for (int i=0; i<counts; i++)
                res *= value;
        std::cout << "res:" <<  res << std::endl;

        return 0;
}

 另外一种方法

#include <stdio.h>

int power(int base, int powerCounts)
{
    int temp=base, result=1;
    do{
        if(powerCounts&1)result*=temp;
        temp*=temp;
    }while(powerCounts>>=1);
    return result;
}

int main()
{
    int r = power(2,10);
    printf("r:%d\n",r);    
    return 0;
}