2的10次方 

 1 #include <iostream>
 2 
 3 int main()
 4 {
 5         int value = 2, counts = 10, res = 1;
 6         for (int i=0; i<counts; i++)
 7                 res *= value;
 8         std::cout << "res:" <<  res << std::endl;
 9 
10         return 0;
11 }

 另外一种方法

#include <stdio.h>

int power(int base, int powerCounts)
{
    int temp=base, result=1;
    do{
        if(powerCounts&1)result*=temp;
        temp*=temp;
    }while(powerCounts>>=1);
    return result;
}

int main()
{
    int r = power(2,10);
    printf("r:%d\n",r);    
    return 0;
}

 

posted on 2013-02-06 14:31  小风儿_xf  阅读(1016)  评论(0)  编辑  收藏  举报

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