摘要：
#includedouble fact(int n);int main(void){int i;double sum;sum=0;for(i=1;i<=100;i++)sum=sum+fact(i);printf("1!+2!+…+100!=%e\n",sum);return 0;}double fact(int n){int i;double result;result=1;for(i=1;i<=n;i++)result=result*i;return result;} 阅读全文
