Compare Version Number

package cn.edu.xidian.sselab.string;

/**
 *
 * @author zhiyong wang
 * title: Compare Version Numbers
 * content:
 * Compare two version numbers version1 and version2.
 * If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.
 *
 * You may assume that the version strings are non-empty and contain only digits and the . character.
 * The . character does not represent a decimal point and is used to separate number sequences.
 * For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.
 *
 * Here is an example of version numbers ordering:
 *
 * 0.1 < 1.1 < 1.2 < 13.37
 *
 */
public class CompareVersionNumbers {

    //参考大牛的做法,这个题首先分裂,然后求出两个数组长度的最大值,用这个大的值进行遍历,如果当前值小于自己的长度,就用自己的值,否则是0,这样进行判断
    public int compareVersion(String version1, String version2){
        String[] v1 = version1.split("\\.");
        String[] v2 = version2.split("\\.");
        int max = v1.length <= v2.length ? v2.length : v1.length;
        for(int i=0;i<max;i++){
            Integer vv1 = i < v1.length ? Integer.valueOf(v1[i]) : 0;
            Integer vv2 = i < v2.length ? Integer.valueOf(v2[i]) : 0;
            if(vv1 > vv2) return 1;
            else if(vv1 < vv2) return -1;
        }
        return 0;                
    }
}

posted on 2016-02-29 21:26  wzyxidian  阅读(258)  评论(0编辑  收藏  举报

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