538. Convert BST to Greater Tree

Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST.

Example:

Input: The root of a Binary Search Tree like this:
              5
            /   \
           2     13

Output: The root of a Greater Tree like this:
             18
            /   \
          20     13
题目含义::给定一棵二叉搜索树,将它转化为更大的二叉树,规则是:结点的值 = 该结点的值 + 所有比它大的结点的值的和。
思路:从右向左依次累加求出总和sum,然后将sum付给当前节点值

 1     int sum = 0;
 2     void convert(TreeNode cur) {
 3         if (cur == null) return;
 4         convert(cur.right);
 5         sum += cur.val;
 6         cur.val = sum;
 7         convert(cur.left);
 8     }
 9     public TreeNode convertBST(TreeNode root) {
10         convert(root);
11         return root;        
12     }

 

posted @ 2017-10-21 22:50  daniel456  阅读(89)  评论(0编辑  收藏  举报