通过http/https的POST方式,发送、处理和接收XML文件内容
1.send:
- C# code
-
WebRequest myHttpWebRequest = WebRequest.Create("http://abc.com/xxx.aspx");
// Set the 'Method' property of the 'Webrequest' to 'POST'.
myHttpWebRequest.Method ="POST";
// Create a new string object to POST data to the Url.
string postData =@"<?xml version="1.0" encoding="UTF-8" ?>
<ROOT>
<CONFIG>
<TYPE>IN </TYPE>
<WORKTYPE>2</WORKTYPE>
</CONFIG>
<DATA>
<POLICY>
<UNITCODE>分公司代码 </UNITCODE>
<APPLYNO>投保单号码 </APPLYNO>
<APPLYENDORSENO>批单申请号码 </APPLYENDORSENO>
</POLICY>
</DATA>
</ROOT>";
ASCIIEncoding encoding =new ASCIIEncoding ();
byte[] byte1 = encoding.GetBytes (postData);
// Set the content type of the data being posted.
myHttpWebRequest.ContentType ="application/x-www-form-urlencoded";
// Set the content length of the string being posted.
myHttpWebRequest.ContentLength = byte1.Length;
Stream newStream = myHttpWebRequest.GetRequestStream ();
newStream.Write (byte1, 0, byte1.Length);
// Close the Stream object.
newStream.Close ();
HttpWebResponse response = myHttpWebRequest.GetResponse();
2.receive:
- C# code
-
StreamReader reader =new StreamReader (Reqeust.InputStream);
String xml = reader.ReadToEnd();
本人博客的文章大部分来自网络转载,因为时间的关系,没有写明转载出处和作者。所以在些郑重的说明:文章只限交流,版权归作者。谢谢