python 获得毫秒级时间戳

import time
import datetime

t = time.time()

print (t)                       #原始时间数据
print (int(t))                  #秒级时间戳
print (int(round(t * 1000)))    #毫秒级时间戳

nowTime = lambda:int(round(t * 1000))
print (nowTime());              #毫秒级时间戳，基于lambda

print (datetime.datetime.now().strftime('%Y-%m-%d %H:%M:%S'))   #日期格式化

结果;

1499825149.26
1499825149
1499825149257
1499825149257
2017-07-12 10:05:49

　

2、将日期转为秒级时间戳

 

dt = '2018-01-01 10:40:30'
ts = int(time.mktime(time.strptime(dt, "%Y-%m-%d %H:%M:%S")))
print (ts)

返回

1514774430

3、将秒级时间戳转为日期

ts = 1515774430
dt = time.strftime("%Y-%m-%d %H:%M:%S", time.localtime(ts))
print(dt)

返回

2018-01-13 00:27:10

转载连接：https://www.cnblogs.com/fangbei/p/python-time.html