Spring MVC中一般 普通类调用service

在Spring MVC中,Controller中使用service只需使用注解@Resource就行,但是一般类(即不使用@Controller注解的类)要用到service时,可用如下方法:

1、SpringContextUtil

package com.test.framework.utils;
 
import org.springframework.beans.BeansException;
import org.springframework.beans.factory.NoSuchBeanDefinitionException;
import org.springframework.context.ApplicationContext;
import org.springframework.context.ApplicationContextAware;
 
public class SpringContextUtil implements ApplicationContextAware {
 
    private static ApplicationContext applicationContext; // Spring应用上下文环境
 
    // 下面的这个方法上加了@Override注解,原因是继承ApplicationContextAware接口是必须实现的方法
    @Override
    public void setApplicationContext(ApplicationContext applicationContext)
            throws BeansException {
        SpringContextUtil.applicationContext = applicationContext;
    }
 
    public static ApplicationContext getApplicationContext() {
        return applicationContext;
    }
 
    public static Object getBean(String name) throws BeansException {
        return applicationContext.getBean(name);
    }
 
    public static Object getBean(String name, Class requiredType)
            throws BeansException {
        return applicationContext.getBean(name, requiredType);
    }
 
    public static boolean containsBean(String name) {
        return applicationContext.containsBean(name);
    }
 
    public static boolean isSingleton(String name) throws NoSuchBeanDefinitionException {
        return applicationContext.isSingleton(name);
    }
 
    public static Class getType(String name)    throws NoSuchBeanDefinitionException {
        return applicationContext.getType(name);
    }
 
    public static String[] getAliases(String name) throws NoSuchBeanDefinitionException {
        return applicationContext.getAliases(name);
    }
}

2、Spring的配置文件application.xml中进行如下配置

<bean id="SpringContextUtil" class="com.test.framework.utils.SpringContextUtil" scope="singleton"></bean>

3、使用

DictService dictService = (DictService) SpringContextUtil.getBean("dictService");
List<dict> dict = (List<dict>) dictService.findByHQL(hql);
posted @ 2018-06-16 14:23  舞羊  阅读(152)  评论(0编辑  收藏  举报