Python基本数据结构之字典嵌套(例子)

北京城市地区之间的嵌套

 1 # coding=gbk
 2 #Created on 2019/5/20
 3 #@author: XiaoHu
 4 
 5 menu = {
 6     '北京': {
 7         '朝阳': {
 8             '国贸': {
 9                 'CICC': {},
10                 'HP': {},
11                 '中国银行': {},
12                 'CCTV': {},
13             },
14             '望京': {
15                 '陌陌': {},
16                 '奔驰': {},
17                 '360': {},
18             },
19             '三里屯': {
20                 '优衣库': {},
21                 'apple': {},
22             },
23         },
24         '昌平': {
25             '沙河': {
26                 "老男孩": {},
27                 "阿泰包子": {},
28             },
29             '天通苑': {
30                 "链家": {},
31                 "我爱我家": {},
32             },
33             '回龙观': {},
34         },
35         '海淀': {
36             "五道口": {
37                 "谷歌": {},
38                 "网易": {},
39                 "Sohu": {},
40                 "快手": {},
41             },
42             "中关村": {
43                 "优酷": {},
44                 "爱奇艺": {},
45                 "汽车之家": {},
46                 "新东方": {},
47                 "QQ": {},
48             },
49         },
50     },
51 
52     '上海': {
53         "浦东": {
54             "陆家嘴": {
55                 "CICC": {},
56                 "高盛": {},
57                 "摩根": {},
58             },
59             "外滩": {},
60         },
61         "闵行": {},
62         "静安": {},
63     },
64 
65     '山东': {
66         "济南": {
67 
68         },
69         "德州": {
70             "乐林": {
71                 "丁坞镇": {},
72                 "城区": {},
73             },
74             "平原": {},
75         },
76         "青岛": {},
77     },
78 }
79 
80 current_layer =  menu
81 parent_layer = menu
82 
83 parent_layers = []
84 
85 while True:
86     for key in current_layer:
87         print(key)
88     choice = input(">>>:").strip()
89     if len(choice) == 0:continue
90     if choice in current_layer:
91         parent_layers.append(current_layer)
92         current_layer = current_layer[choice]
93     elif choice == "b":
94         if parent_layers:
95             current_layer = parent_layers.pop()
96     else:
97         print("无此项")

 

posted @ 2019-08-08 21:04  Xiaohu_BigData  阅读(806)  评论(0编辑  收藏  举报