tomcat中的简单CXF webservice

tomcat中使用cxf做的webservice服务端,需要一个sevlet来管理webservice服务端

需要在web.xml中加入如下代码

    <servlet>
          <servlet-name>CXFServlet</servlet-name>
              <servlet-class>
                  cn.jsprun.ws.StartUpListener
              </servlet-class>
            <load-on-startup>1</load-on-startup>
     </servlet>

    <servlet-mapping>
       <servlet-name>CXFServlet</servlet-name>
       <url-pattern>/service/*</url-pattern>
    </servlet-mapping>

StartUpListener类要继承CXFNonSpringServlet:

package cn.jsprun.ws;

import javax.servlet.ServletConfig;
import javax.servlet.ServletContextEvent;
import javax.servlet.ServletContextListener;
import javax.servlet.http.HttpSessionEvent;
import javax.servlet.http.HttpSessionListener;
import javax.xml.ws.Endpoint;

import org.apache.cxf.transport.servlet.CXFNonSpringServlet;


public class StartUpListener  extends CXFNonSpringServlet{
    
    @Override  
    public void loadBus(ServletConfig servletConfig) {   
        super.loadBus(servletConfig);
        
        System.out.println("web service start");
        HotTopicImpl implementor = new HotTopicImpl();
        String address = "/hotTopic.do";
        Endpoint.publish(address, implementor);
        System.out.println("web service started");
        
    } 
}

这样webservice服务就建立了

启动tomcat,在url中输入http://localhost:8080/mytest/service/hotTopic.do?wsdl来验证是否webservice是否创建成功

 

 

posted @ 2012-11-15 22:47  小虾Joe  阅读(2618)  评论(0编辑  收藏  举报