LeetCode - 661. Image Smoother
Given a 2D integer matrix M representing the gray scale of an image, you need to design a smoother to make the gray scale of each cell becomes the average gray scale (rounding down) of all the 8 surrounding cells and itself. If a cell has less than 8 surrounding cells, then use as many as you can.
Example 1:
Input: [[1,1,1], [1,0,1], [1,1,1]] Output: [[0, 0, 0], [0, 0, 0], [0, 0, 0]] Explanation: For the point (0,0), (0,2), (2,0), (2,2): floor(3/4) = floor(0.75) = 0 For the point (0,1), (1,0), (1,2), (2,1): floor(5/6) = floor(0.83333333) = 0 For the point (1,1): floor(8/9) = floor(0.88888889) = 0
class Solution { public int[][] imageSmoother(int[][] m) { if (m == null) return null; int[][] ret = new int[m.length][m[0].length]; for (int i=0; i<m.length; i++) { for (int j=0; j<m[i].length; j++) { int sum = m[i][j], cnt = 1; if (i-1 >= 0) { sum += m[i-1][j];cnt++; if (j-1 >= 0) { sum += m[i-1][j-1]; cnt ++; } if (j+1 < m[i].length) { sum += m[i-1][j+1]; cnt ++; } } if (i+1 < m.length) { sum += m[i+1][j];cnt++; if (j-1 >= 0) { sum += m[i+1][j-1]; cnt++; } if (j+1 < m[i].length) { sum += m[i+1][j+1]; cnt++; } } if (j-1 >= 0) { sum += m[i][j-1]; cnt++; } if (j+1 < m[i].length) { sum += m[i][j+1]; cnt++; } ret[i][j] = sum / cnt; } } return ret; } }
作者:Pickle
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