LeetCode - 537. Complex Number Multiplication
Given two strings representing two complex numbers.
You need to return a string representing their multiplication. Note i2 = -1 according to the definition.
Example 1:
Input: "1+1i", "1+1i" Output: "0+2i" Explanation: (1 + i) * (1 + i) = 1 + i2 + 2 * i = 2i, and you need convert it to the form of 0+2i.
Example 2:
Input: "1+-1i", "1+-1i" Output: "0+-2i" Explanation: (1 - i) * (1 - i) = 1 + i2 - 2 * i = -2i, and you need convert it to the form of 0+-2i.
Note:
- The input strings will not have extra blank.
- The input strings will be given in the form of a+bi, where the integer a and b will both belong to the range of [-100, 100]. And the output should be also in this form.
public class Solution { public String complexNumberMultiply(String a, String b) { if (a == null || b == null) return null; String[] ap = a.split("\\+"); int p1 = Integer.parseInt(ap[0]); int k1 = Integer.parseInt(ap[1].substring(0, ap[1].length()-1)); String[] bp = b.split("\\+"); int p2 = Integer.parseInt(bp[0]); int k2 = Integer.parseInt(bp[1].substring(0, bp[1].length()-1)); int r1 = p1*p2; int ri = p1*k2 + k1*p2; int ri2 = -(k1*k2); int p3 = r1 + ri2; int k3 = ri; return p3+"+"+k3+"i"; } }
作者:Pickle
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