字符流中第一个不重复的字符
请实现一个函数用来找出字符流中第一个只出现一次的字符。例如,当从字符流中只读出前两个字符"go"时,第一个只出现一次的字符是"g"。当从该字符流中读出前六个字符“google"时,第一个只出现一次的字符是"l"。
如果当前字符流没有存在出现一次的字符,返回#字符。
import java.util.*; public class Solution { private int[] cache = new int[500]; private List<Character> chs = new ArrayList<Character>(); public Solution() { Arrays.fill(cache, 0); } //Insert one char from stringstream public void Insert(char ch) { chs.add(ch); cache[(int)ch] ++; } //return the first appearence once char in current stringstream public char FirstAppearingOnce() { for (int i=0; i<chs.size(); i++) { if (cache[(int)chs.get(i)] == 1) { return chs.get(i); } } return '#'; } }
作者:Pickle
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