二叉树的镜像
题目:
操作给定的二叉树,将其变换为源二叉树的镜像。
二叉树的镜像定义:源二叉树 8 / \ 6 10 / \ / \ 5 7 9 11 镜像二叉树 8 / \ 10 6 / \ / \ 11 9 7 5
思路:这就是著名的反转二叉树?递归的交换左右子树就可以了,注意递归结束的条件。
实现代码:
/** public class TreeNode { int val = 0; TreeNode left = null; TreeNode right = null; public TreeNode(int val) { this.val = val; } } */ public class Solution { public void Mirror(TreeNode root) { if(root == null) return ; if(root.left == null && root.right == null) return ; TreeNode temp = root.left; root.left = root.right; root.right = temp; Mirror(root.left); Mirror(root.right); } }
作者:Pickle
声明:对于转载分享我是没有意见的,出于对博客园社区和作者的尊重一定要保留原文地址哈。
致读者:坚持写博客不容易,写高质量博客更难,我也在不断的学习和进步,希望和所有同路人一道用技术来改变生活。觉得有点用就点个赞哈。
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