LeetCode——Search for a Range
Description:
Given a sorted array of integers, find the starting and ending position of a given target value.
Your algorithm's runtime complexity must be in the order of O(log n).
If the target is not found in the array, return [-1, -1]
.
For example, Given [5, 7, 7, 8, 8, 10]
and target value 8, return [3, 4]
.
public class Solution { public int[] searchRange(int[] nums, int target) { int flag = -1, start=-1, end = -1; for(int i=0; i<nums.length; i++) { if(nums[i] == target) { start = i; for(int j=i; j<nums.length; j++) { if(nums[j] != target) { end = j-1; flag = 1; break; } if(nums[j]==target && j==nums.length-1) { end = j; flag = 1; break; } } } if(flag == 1) { break; } } return new int[]{start, end}; } }
作者:Pickle
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致读者:坚持写博客不容易,写高质量博客更难,我也在不断的学习和进步,希望和所有同路人一道用技术来改变生活。觉得有点用就点个赞哈。
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