LeetCode——Intersection of Two Linked Lists
Description:
Write a program to find the node at which the intersection of two singly linked lists begins.
For example, the following two linked lists:
A: a1 → a2 ↘ c1 → c2 → c3 ↗ B: b1 → b2 → b3
begin to intersect at node c1.
求两个链表的相交的部分
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { * val = x; * next = null; * } * } */ public class Solution { public ListNode getIntersectionNode(ListNode headA, ListNode headB) { if(headA==null || headB==null) return null; ListNode aNode = headA; ListNode bNode = headB; int aLen = 0, bLen = 0; while(aNode != null) { aLen ++; aNode = aNode.next; } while(bNode != null) { bLen ++; bNode = bNode.next; } if(aNode != bNode) return null; if(aLen > bLen) { for(int i = 0; i < aLen-bLen; i++) headA = headA.next; } else if(aLen < bLen) { for(int i=0; i<bLen-aLen; i++) headB = headB.next; } while(headA != headB) { headA = headA.next; headB = headB.next; } return headA; } }
作者:Pickle
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