LeetCode——Invert Binary Tree
Description:
Invert a binary tree.
4
/ \
2 7
/ \ / \
1 3 6 9
to
4
/ \
7 2
/ \ / \
9 6 3 1
递归invert就好了。
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public TreeNode invertTree(TreeNode root) { if(root == null) return null; invert(root); return root; } public static void invert(TreeNode root) { if(root==null || (root.right == null && root.left==null)) { return; } TreeNode rNode = root.right; TreeNode lNode = root.left; root.right = lNode; root.left = rNode; invert(root.left); invert(root.right); } }
作者:Pickle
声明:对于转载分享我是没有意见的,出于对博客园社区和作者的尊重一定要保留原文地址哈。
致读者:坚持写博客不容易,写高质量博客更难,我也在不断的学习和进步,希望和所有同路人一道用技术来改变生活。觉得有点用就点个赞哈。
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