LeetCode——Number of 1 Bits
//求一个整数的二进制串中1的个数
public int hammingWeight(int n) { String b_str = Integer.toBinaryString(n); int b_count = 0; for(int i=0; i<b_str.length(); i++) { if(b_str.charAt(i) == '1') { b_count ++; } } return b_count; }
作者:Pickle
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