层次查询

 

select employee_id,last_name,manager_id,

level,lpad(' ',level*5)||last_name AS name

from employees

where rownum<30

start with manager_id=100

connect by prior employee_id=manager_id;

posted @ 2014-11-30 11:01  智能先行者  阅读(169)  评论(0编辑  收藏  举报