BigDecimal计算开方

?

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30

public static void main(String[] args) {         BigDecimal big = new BigDecimal("68");         BigDecimal reuturn = sqrt(big,2);         String result = reuturn.stripTrailingZeros().toPlainString();         System.out.println("result= "+result);//8.25     }           /**      *      * @Title: sqrt      * @Description: TODO 计算开方      * @param value  要计算的数字      * @param scale  保留多少小数位      * @return      * @Author:wushigao      * @CreateDate:2022年10月10日 下午2:34:09      */     public static BigDecimal sqrt(BigDecimal value, int scale){         BigDecimal num2 = BigDecimal.valueOf(2);         int precision = 100;         MathContext mc = new MathContext(precision, RoundingMode.HALF_UP);         BigDecimal deviation = value;         int cnt = 0;         while (cnt < precision) {             deviation = (deviation.add(value.divide(deviation, mc))).divide(num2, mc);             cnt++;         }         deviation = deviation.setScale(scale, BigDecimal.ROUND_HALF_UP);         return deviation;     }