关于ArrayList的contains方法

需求：只要名字相同，就判断是同一个用户

 1、重写equals方法

    public static class Student{
        private String name;
        private int age;
        
//        @Override
//        public int hashCode(){
//            final int prime = 31;
//            int result = 1;
//            result = prime * result + ((name == null) ? 0 : name.hashCode());
//            return result;
//        }
        @Override
        public boolean equals(Object antObject){
            if(this == antObject){
                return true;
            }
            if(antObject instanceof Student){
                Student anotherStu = (Student) antObject;
                if(this.name.equals(anotherStu.name) && this.age == anotherStu.age){
                    return true;
                }
                return false;
            }
            return false;
        }
        public String getName() {
            return name;
        }
        public void setName(String name) {
            this.name = name;
        }
        public int getAge() {
            return age;
        }
        public void setAge(int age) {
            this.age = age;
        }
    }

2、运行结果