看来作为码农得天天写代码啊[hdu1228]

直接上代码：

  1 #include<stdio.h>
  2 #include<string.h>
  3 #include<stdlib.h>
  4 
  5 
  6  const char* numbers[]={"zero","one","two","three","four","five","six",\
  7     "seven","eight","nine",NULL};
  8 
  9  int read_word(char*num,char**at)
 10 {
 11     char* start;
 12     if(!**at)
 13         return 0;
 14 
 15     start = *at;
 16     while(**at!=' ' && **at!='\0')
 17     {
 18         (*at)++;
 19     }
 20     **at = '\0';
 21     (*at)++;
 22     if(*start <'a' || *start > 'z')
 23     {
 24         return 0;
 25     }
 26     strcpy(num,start);
 27     //now skip to the nonspace 
 28      while(**at==' ' && **at!='\0')
 29         (*at)++;
 30     return 1;
 31 }
 32 
 33 int word2num(const char* num)
 34 {
 35     int rt=0;
 36     const char** i = numbers;
 37     while(*i)
 38     {
 39         if(!strcmp(*i,num))
 40             return rt;
 41         rt++;
 42         i++;
 43     }
 44     return rt;
 45 }
 46 
 47 
 48 int main()
 49 {
 50     char* line;
 51     char* num;
 52     int done=0;
 53     line = (char*)malloc(50*sizeof(char));
 54     num = (char*)malloc(10*sizeof(char));
 55 
 56     
 57     while(!done)
 58     {
 59         int add11,add12,add21,add22;
 60         char* at;
 61         int rt;
 62         fgets(line,50,stdin);
 63         
 64         add11=add12=add21=add22=0;
 65          at = line;
 66             
 67         //oprand 1
 68         rt = read_word(num,&at);
 69         if(!rt)
 70         {
 71             printf("input error!\n");
 72             return 0;
 73         }
 74         add11 = word2num(num);
 75         //read the second num and skip the + or skip the +
 76         if(read_word(num,&at))
 77         {
 78             add12 = word2num(num);
 79             add11=add11*10;
 80             read_word(num,&at);//skip the +
 81         }
 82         //anther oprand
 83         read_word(num,&at);
 84         add21 = word2num(num);
 85         if(read_word(num,&at))
 86         {
 87             add21=add21*10;
 88             add22= word2num(num);
 89         }
 90         if(add11==0&&add12==0&&add21==0&&add22==0)
 91         {
 92             done = 1;
 93             break;
 94         }
 95         printf("%d\n",add11+add12+add21+add22);
 96     }
 97     free(num);
 98     free(line);
 99     return 0;
100 }
101 
102         
103         
104

顺便说一下，hdu的gcc编译器什么版本，连//风格的注释都不支持...囧！

posted on 2011-03-07 21:00  Weifeng Wang  阅读(534)  评论(0)  编辑  收藏  举报

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