【JavaScript】网传字节跳动面试题：实现一个32进制的加法
【编程题】实现一个 36 进制的加法 0-9 a-z。
输入 abbbb 1 输出 abbbc
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Document</title>
</head>
<body>
<input type="text" id="input1" />
<input type="text" id="input2" />
<span id="show"></span>
<button onclick="calcu()">计算</button>
<script>
function calcu() {
var num1 = document.getElementById("input1").value;
var num2 = document.getElementById("input2").value;
var arr1 = num1.split("");
var arr2 = num2.split("");
var result = []
arr1 = arr1.reverse()
arr2 = arr2.reverse()
// console.log(arr1, arr2)
if (arr1.length < arr2.length) {
var temp = arr1;
arr1 = arr2;
arr2 = temp;
}
var jinwei = 0;// 一开始没有进位
arr1.map((t, i) => {
var sum = 0;
if (arr2[i]) {
sum = getInt(t) + getInt(arr2[i]) + jinwei;
} else {
sum = getInt(t) + jinwei;
jinwei = 0;//从此不再有进位
}
result.push(getChar(sum))
});
console.log("结果：" + result.reverse().join())
document.getElementById("show").innerText = result.join();
}
// 基于ascii,将十进制整数转化为 36进制字符
function getChar(num) {
if (num <= 9) {
return String.fromCharCode("0".charCodeAt(0) + num);
} else {
return String.fromCharCode(num - 10 + "a".charCodeAt(0));
}
}
// 基于ascii，将36 进制字符转化为 10进制整数
function getInt(char) {
if (char.charCodeAt(0) <= "9".charCodeAt(0)) {
return char.charCodeAt(0) - "0".charCodeAt(0);
} else {
return char.charCodeAt(0) - "a".charCodeAt(0) + 10;
}
}
</script>
</body>
</html>
